If that's not the case and per(:,:,1) is the same size as img_idim then flip the arguments. This assumes imq_idim is the same size as m_source. Out in this case will have the shape of A, and contains only items that are in both A and B. Return indices of matrix A that match an item in matrix B out = ismember(A,B) Do I need the matrices m_source and n_source, which are just the real source images row, rsp. Apparently I have to tell MATLAB over what index vector (is that how you call it?) the function should be applied and the two colons are not sufficient. Imp_double(:,:,idim) = imq_idim(m_source_q=per(:,:,1) & n_source_q=per(:,:,2)) īut the interpreter complains the sizes of the matrices don't match. My question: How can I avoid the for loops by logical indexing, or by some other method? This works, but it takes really too long, and I'm pretty sure that the two nested for loops are the cause of this. height of projection imageįor n=1:Wp % Wp. The last step is mapping the projections pixels to the corresponding interpolated color values: for idim=1:3įor m=1:Hp % Hp. Will just be converted to projection_image = uint8(imp_double). Imp_double is a 3-D matrix that contains the (double type / real number) color values of all color channels for every projection image pixel. Note that idim is the index of the color channel (R: 1, G: 2, B: 3) Imq(:,:,idim) = interp2(n_source, m_source, imsource(:,:,idim), n_source_q, m_source_q, 'linear') Imq is a 3-D matrix that contains all interpolated color values for every color channel and for every grid position. so for example p_er(502, 262, 1) = 259.9 (corresponding row in original image) p_er(592, 252, 2) = 513.2 (corresponding column in original image). it is a two-dimensional map that contains the fractioned coordinates of the interpolated original image for every pixel on the projection image. N_source_q likewise contains the query column position [1 1.1 1.2 1.3. M_source_q is a 2 dimensional matrix, containing the row of the interpolation (query) grid, so for a 1024*512 original image and a grid precision of 0.1 pixels m_source_q looks like: [1 1 1 1. Im_source is a 3 dimensional matrix, ordered by (row, column, color_channel), containing the value of the particular color channel Since the positions on the equirectangular image are often non inter numbers because of the projection (trigonomical and other functions) the color values of the projection images pixels have to be interpolated from the color values of the source image. This is done by locating every pixel on the projection image (destination) on the equirectangular image (input). ** Doubles the first 5 elements of the array */įor (int i = 0 i < values.My program transforms an original equirectangular image into an azimuthal orthographic projection. What will the following code print out? Can you write a similar method called tripleFirstFour() that triples the first 4 elements of the array? Make sure you test it in main. It is created in the constructor and changed or accessed by the methods. Notice that it uses a complex conditional ( &) on line 14 to make sure that the loop doesn’t go beyond the length of the array, because if you had an array that had less than 5 elements, you wouldn’t want the code to try to double the 5th element which doesn’t exist! Notice that in this code, the array is a private instance variable of the class ArrayWorker. The following code doubles the first five elements in an array. You can loop through just some of the elements of an array using a for loop. You don’t have to loop through all of the elements of an array. You must start at the length of the array minus one.
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